Q&A: Halakhic Examples of Mistaken Use of Conditional Probability (Column 145)
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Halakhic Examples of Mistaken Use of Conditional Probability (Column 145)
Question
It seems that what follows from what you wrote is that in a panel of three, the odds ratios are as follows: 1. two are right to two are wrong 2. one is right to one is wrong — they are equal (p/(1-p
and an advantage to the majority view exists only with four and above.
Is that really so?
Answer
Please update this in its proper place, otherwise it will be deleted.